WhyInitiation is the homolytic splitting of $\text{Cl}_{2}$ by UV light into two chlorine radicals: $\text{Cl}_{2} \rightarrow 2\text{Cl}\bullet$.
4Multiple choice · Medium
A termination step in a radical chain reaction is one in which:
Two radicals combine to form a molecule
A radical reacts to form another radical
A bond splits to form radicals
A catalyst is added
Tap an answer to check it.
WhyTermination removes radicals by combining two of them to form a stable molecule, e.g. $\text{CH}_{3}\bullet + \text{Cl}\bullet \rightarrow \text{CH}_{3}\text{Cl}$.
5Multiple choice · Medium
What are the products of the monochlorination (single substitution) of methane?
$\text{CH}_{3}\text{Cl}$ and $\text{HCl}$
$\text{CH}_{2}\text{Cl}_{2}$ and $\text{H}_{2}$
$\text{CCl}_{4}$ and $\text{HCl}$
$\text{CH}_{4}$ and $\text{Cl}_{2}$
Tap an answer to check it.
WhyOne H is replaced by Cl, giving chloromethane and hydrogen chloride: $\text{CH}_{4} + \text{Cl}_{2} \rightarrow \text{CH}_{3}\text{Cl} + \text{HCl}$.
6Multiple choice · Hard
Which step regenerates reactive radicals so that the chain reaction can continue?
Propagation
Termination
Neutralisation
Hydrolysis
Tap an answer to check it.
WhyIn propagation steps a radical reacts with a molecule to form a product and a new radical, sustaining the chain, e.g. $\text{CH}_{4} + \text{Cl}\bullet \rightarrow \text{CH}_{3}\bullet + \text{HCl}$.
7Fill in the blank · Easy
A species that contains an unpaired electron and is highly reactive is called a .
Answer:
radical / free radical
WhyA free radical has an unpaired electron, usually shown with a dot, e.g. $\text{Cl}\bullet$.
8Fill in the blank · Medium
The first step of free-radical substitution, in which UV light splits $\text{Cl}_{2}$ into radicals, is called .
Answer:
initiation
WhyInitiation creates the first radicals by homolytic fission of the halogen molecule under UV light.
9Multiple choice · Medium
Which species forms when Br2 undergoes homolytic fission in UV light?
Two bromine radicals (Br with one unpaired electron)
A Br+ and a Br- ion
Two Br- ions
A Br2- ion
Tap an answer to check it.
WhyHomolytic fission splits the bond evenly, giving two bromine radicals, each written Br with a single unpaired electron.
10Multiple choice · Medium
When one covalent bond in CHCl2F breaks homolytically in the upper atmosphere, the weakest bond breaks. Which radical is most likely formed?
A radical with formula CHClF
A radical with formula CCl2F
A radical with formula CHCl2
A radical with formula CHCl2F
Tap an answer to check it.
WhyThe C-Cl bond is weakest, so a chlorine atom leaves, giving the radical with formula CHClF.
Ready to test yourself?
Practise Electron sharing reactions with instant marking and per-topic score tracking.