WhyAn exothermic reaction releases heat to the surroundings and has a negative enthalpy change ($\Delta H < 0$).
2Multiple choice · Easy
During an endothermic reaction the temperature of the surroundings:
Decreases
Increases
Stays the same
Doubles
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WhyAn endothermic reaction absorbs heat from the surroundings, so the temperature of the surroundings falls.
3Multiple choice · Medium
Which equation is used to calculate the heat energy transferred to or from water in calorimetry?
$q = mc\Delta T$
$q = \dfrac{m}{c\Delta T}$
$q = nRT$
$q = mc + \Delta T$
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WhyThe heat transferred is $q = mc\Delta T$, where $m$ is the mass, $c$ the specific heat capacity and $\Delta T$ the temperature change.
4Multiple choice · Medium
In what units is an enthalpy change of reaction usually expressed?
$\text{kJ mol}^{-1}$
$\text{g}$
$\text{mol dm}^{-3}$
$\text{K}$
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WhyEnthalpy changes of reaction are usually quoted per mole of reaction in $\text{kJ mol}^{-1}$.
5Multiple choice · Medium
When a fuel is burned under a beaker of water, the heat released by the fuel is assumed to be equal to:
The heat gained by the water, $mc\Delta T$
The mass of fuel burned
The activation energy
Zero
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WhyIn simple calorimetry it is assumed all the heat released by the reaction is absorbed by the water, so heat released $= mc\Delta T$ of the water.
6Multiple choice · Hard
Burning $0.0100\,\text{mol}$ of a fuel raises the temperature of $100\,\text{g}$ of water by $20.0\,^{\circ}\text{C}$. Using $c = 4.18\,\text{J g}^{-1}\,^{\circ}\text{C}^{-1}$, what is the enthalpy of combustion?
$-836\,\text{kJ mol}^{-1}$
$-8.36\,\text{kJ mol}^{-1}$
$+836\,\text{kJ mol}^{-1}$
$-83.6\,\text{kJ mol}^{-1}$
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Why$q = mc\Delta T = 100 \times 4.18 \times 20.0 = 8360\,\text{J} = 8.36\,\text{kJ}$. Per mole: $\Delta H = -8.36/0.0100 = -836\,\text{kJ mol}^{-1}$ (negative, exothermic).
7Fill in the blank · Easy
The breaking of chemical bonds is an process (it absorbs energy).
Answer:
endothermic
WhyBond breaking requires energy input (endothermic), while bond making releases energy (exothermic).
8Fill in the blank · Medium
Heating $100\,\text{g}$ of water by $5.0\,^{\circ}\text{C}$ ($c = 4.18\,\text{J g}^{-1}\,^{\circ}\text{C}^{-1}$) requires J of heat.